124=4*2^(n-1)

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Solution for 124=4*2^(n-1) equation: 



124=4*2^(n-1)

We move all terms to the left:

124-(4*2^(n-1))=0



We calculate terms in parentheses: -(4*2^(n-1)), so:

4*2^(n-1)

Wy multiply elements

8n(n

Back to the equation:

-(8n(n)

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